Matematika (4)^-2+(1/3)^3

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(4)^-2+(1/3)^3

Tolong dijawab ya kak

Penjelasan dengan langkah-langkah:

[tex] {4}^{ - 2} + ({ \frac{1}{3} })^{3} \\ = \frac{1}{ {4}^{2} } + \frac{1}{ {3}^{3} } \\ = \frac{1}{16} + \frac{1}{27} \\ = \frac{27}{432} + \frac{16}{432} \\ = \frac{43}{432} [/tex]

-sy

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